What is the answer to 4log_{5}(x+1)=4.8 ?

The answer to 4log_{5}(x+1)=4.8 is x=5^{1.2}-1

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4log_{5}(x+1)=4.8

4 lo g_{5} (x + 1) = 4.8

x = 5^{1.2} - 1

Decimal

x = 5.89864 \dots

Solution steps

4 lo g_{5} (x + 1) = 4.8

Divide both sides by

4

lo g_{5} (x + 1) = 1.2

Apply log rules

x + 1 = 5^{1.2}

Solve

x + 1 = 5^{1.2} : x = 5^{1.2} - 1

x = 5^{1.2} - 1

Verify Solutions:

x = 5^{1.2} - 1

True

The solution is

x = 5^{1.2} - 1

lo g_{x + 7} (3 x^{2} + 6 x - 15) = 2

y, y = ln (x y)

lo g_{2 x} (x^{2} + 9 x - 6) = 2

lo g_{0.2} (2 x - 3) = - 1

ln (x) = \frac{x}{2}

What is the answer to 4log_{5}(x+1)=4.8 ?
The answer to 4log_{5}(x+1)=4.8 is x=5^{1.2}-1
Solve for x: 4log_{5}(x+1)=4.8
The solution is x=5^{1.2}-1