What is the answer to ln(x^2-2x+7/4)=0 ?

The answer to ln(x^2-2x+7/4)=0 is x= 3/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(x^2-2x+7/4)=0

ln (x^{2} - 2 x + \frac{7}{4}) = 0

x = \frac{3}{2}, x = \frac{1}{2}

Decimal

x = 1.5, x = 0.5

Solution steps

ln (x^{2} - 2 x + \frac{7}{4}) = 0

Apply log rules

x^{2} - 2 x + \frac{7}{4} = 1

Solve

x^{2} - 2 x + \frac{7}{4} = 1 : x = \frac{3}{2}, x = \frac{1}{2}

x = \frac{3}{2}, x = \frac{1}{2}

282 = 122 lo g_{10} (0.8 x) + 85

ln (x) = 5.2339583

lo g_{3} (5 x + 1) = 4

lo g_{2} (x) = 5

lo g_{2} (x - 8) = 4

What is the answer to ln(x^2-2x+7/4)=0 ?
The answer to ln(x^2-2x+7/4)=0 is x= 3/2 ,x= 1/2
Solve for x: ln(x^2-2x+7/4)=0
The solution is x= 3/2 ,x= 1/2