What is the answer to log_{7}(3-x)=2log_{7}(4) ?

The answer to log_{7}(3-x)=2log_{7}(4) is x=-13

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log_{7}(3-x)=2log_{7}(4)

lo g_{7} (3 - x) = 2 lo g_{7} (4)

x = - 13

Solution steps

lo g_{7} (3 - x) = 2 lo g_{7} (4)

Apply log rules

3 - x = 16

Solve

3 - x = 16 : x = - 13

x = - 13

Verify Solutions:

x = - 13

True

The solution is

x = - 13

lo g_{10} (a) = 4

lo g_{10} (x) = 40.92

lo g_{\frac{1}{3}} (4 x - 5) = - 2

3 lo g_{2} (x + 4) = 9

lo g_{10} (7 x) = lo g_{10} (37) + 5 lo g_{10} (x)

What is the answer to log_{7}(3-x)=2log_{7}(4) ?
The answer to log_{7}(3-x)=2log_{7}(4) is x=-13
Solve for x: log_{7}(3-x)=2log_{7}(4)
The solution is x=-13