What is the answer to log_{1/27}(4x+1)=-1 ?

The answer to log_{1/27}(4x+1)=-1 is x= 13/2

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log_{1/27}(4x+1)=-1

lo g_{\frac{1}{27}} (4 x + 1) = - 1

x = \frac{13}{2}

Decimal

x = 6.5

Solution steps

lo g_{\frac{1}{27}} (4 x + 1) = - 1

Apply log rules

4 x + 1 = 27

Solve

4 x + 1 = 27 : x = \frac{13}{2}

x = \frac{13}{2}

lo g_{\frac{1}{2}} (x - 3) = 0

lo g_{x} (3) = 41

lo g_{b} (16) = - 4

lo g_{10} (5 x) = 6

lo g_{7} (x^{2} - x + 1) = 1

What is the answer to log_{1/27}(4x+1)=-1 ?
The answer to log_{1/27}(4x+1)=-1 is x= 13/2
Solve for x: log_{1/27}(4x+1)=-1
The solution is x= 13/2