What is the answer to log_{2}(x^2+7)=4 ?

The answer to log_{2}(x^2+7)=4 is x=3,x=-3

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log_{2}(x^2+7)=4

lo g_{2} (x^{2} + 7) = 4

x = 3, x = - 3

Solution steps

lo g_{2} (x^{2} + 7) = 4

Apply log rules

x^{2} + 7 = 16

Solve

x^{2} + 7 = 16 : x = 3, x = - 3

x = 3, x = - 3

lo g_{x} (12) = 0.1

E, lo g (\frac{r ^{2}}{Ep}) = lo g (4)

lo g_{32} (x) = \frac{3}{5}

lo g_{x} (5) = 4

- lo g_{10} (x) = 11.5

What is the answer to log_{2}(x^2+7)=4 ?
The answer to log_{2}(x^2+7)=4 is x=3,x=-3
Solve for x: log_{2}(x^2+7)=4
The solution is x=3,x=-3