What is the answer to 1+5log_{10}(x^2+1)=6 ?

The answer to 1+5log_{10}(x^2+1)=6 is x=3,x=-3

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1+5log_{10}(x^2+1)=6

1 + 5 lo g_{10} (x^{2} + 1) = 6

x = 3, x = - 3

Solution steps

1 + 5 lo g_{10} (x^{2} + 1) = 6

Move

1

to the right side

5 lo g_{10} (x^{2} + 1) = 5

Divide both sides by

5

lo g_{10} (x^{2} + 1) = 1

Apply log rules

x^{2} + 1 = 10

Solve

x^{2} + 1 = 10 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

2 lo g_{10} (x) + 3 = 5 lo g_{10} (x)

6 x ln (\frac{1}{x}) - x = 0

lo g_{0.125 x} (8) = 0

lo g_{x - 1} (32) = 5

lo g_{\frac{1}{2}} (5 + 4 x) = - 2

What is the answer to 1+5log_{10}(x^2+1)=6 ?
The answer to 1+5log_{10}(x^2+1)=6 is x=3,x=-3
Solve for x: 1+5log_{10}(x^2+1)=6
The solution is x=3,x=-3