What is the answer to ln(2x)+ln(3)=4 ?

The answer to ln(2x)+ln(3)=4 is x=(e^4)/6

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ln(2x)+ln(3)=4

ln (2 x) + ln (3) = 4

x = \frac{e ^{4}}{6}

Decimal

x = 9.09969 \dots

Solution steps

ln (2 x) + ln (3) = 4

Move

ln (3)

to the right side

ln (2 x) = 4 - ln (3)

Apply log rules

2 x = \frac{e ^{4}}{3}

Solve

2 x = \frac{e ^{4}}{3} : x = \frac{e ^{4}}{6}

x = \frac{e ^{4}}{6}

Verify Solutions:

x = \frac{e ^{4}}{6}

True

The solution is

x = \frac{e ^{4}}{6}

x^{- 3} = lo g_{3} (x)

2 ln (x) = ln (4)

ln (x^{2} + 1) = 8

ln (x + 8) = 3

8 + lo g_{8} (x) = 8

What is the answer to ln(2x)+ln(3)=4 ?
The answer to ln(2x)+ln(3)=4 is x=(e^4)/6
Solve for x: ln(2x)+ln(3)=4
The solution is x=(e^4)/6