What is the answer to log_{5}(-6x)=3 ?

The answer to log_{5}(-6x)=3 is x=-125/6

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log_{5}(-6x)=3

lo g_{5} (- 6 x) = 3

x = - \frac{125}{6}

Decimal

x = - 20.83333 \dots

Solution steps

lo g_{5} (- 6 x) = 3

Apply log rules

- 6 x = 125

Solve

- 6 x = 125 : x = - \frac{125}{6}

x = - \frac{125}{6}

lo g_{\frac{1}{2}} (x - 6) = - 2

- 50 = 10 lo g_{10} (\frac{p}{1})

lo g_{4} (x) = lo g_{x} (64)

lo g_{11} (7 t + 2) = 2

ln (x + 6) - ln (x) = 1