What is the answer to log_{x}(1/32)=-5/4 ?

The answer to log_{x}(1/32)=-5/4 is x=16

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log_{x}(1/32)=-5/4

lo g_{x} (\frac{1}{32}) = - \frac{5}{4}

x = 16

Solution steps

lo g_{x} (\frac{1}{32}) = - \frac{5}{4}

Apply log rules

\frac{ln ( \frac{1}{32} )}{ln ( x )} = - \frac{5}{4}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

ln (\frac{1}{32}) \cdot 4 = - ln (x) \cdot 5

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

(y + 4) ln (2 y + 3) = 0

lo g_{3} (2 x - 7) = 2

4.47 = - lo g_{10} (x)

lo g_{10} (x - 1) = 1

lo g_{2} (x - 2) = \frac{2}{3} x - 2

What is the answer to log_{x}(1/32)=-5/4 ?
The answer to log_{x}(1/32)=-5/4 is x=16
Solve for x: log_{x}(1/32)=-5/4
The solution is x=16