What is the answer to log_{2}(8x+1)=4 ?

The answer to log_{2}(8x+1)=4 is x= 15/8

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log_{2}(8x+1)=4

lo g_{2} (8 x + 1) = 4

x = \frac{15}{8}

Decimal

x = 1.875

Solution steps

lo g_{2} (8 x + 1) = 4

Apply log rules

8 x + 1 = 16

Solve

8 x + 1 = 16 : x = \frac{15}{8}

x = \frac{15}{8}

lo g_{10} (x^{4} - 4) - lo g_{10} (x^{2} + 2) = 0

2 lo g_{7} (x - 1) = 0

x, 5 x + 3 ln (x - 4) = 25

10 lo g_{10} (\frac{x}{20}) = 5

lo g_{a} (16) = \frac{1}{2}

What is the answer to log_{2}(8x+1)=4 ?
The answer to log_{2}(8x+1)=4 is x= 15/8
Solve for x: log_{2}(8x+1)=4
The solution is x= 15/8