What is the answer to |x^2+x-5|=x^2+5 ?

The answer to |x^2+x-5|=x^2+5 is x=-1/2 \lor x=0\lor x=10

Solve for x: |x^2+x-5|=x^2+5

The solution is x=-1/2 \lor x=0\lor x=10

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x^{2} + x - 5 = x^{2} + 5

x = - \frac{1}{2} or x = 0 or x = 10

Decimal

x = - 0.5, x = 0, x = 10

Solution steps

x^{2} + x - 5 = x^{2} + 5

Find positive and negative intervals

x \leq \frac{- 21 - 1}{2}, \frac{- 21 - 1}{2} < x < \frac{21 - 1}{2}, x \geq \frac{21 - 1}{2}

Solve the inequality for each interval

No Solution or (x = - \frac{1}{2} or x = 0) or x = 10

x = - \frac{1}{2} or x = 0 or x = 10

2 ∣ x - 6 ∣ - 16 = 6 x

∣ x + 5 ∣ = 1

\frac{5 ∣ 2 x - 4 ∣}{4} = 10

3 x^{2} - 17 x + 10 = 10

4 ∣ p - 3 ∣ = ∣ 2 p + 8 ∣

What is the answer to |x^2+x-5|=x^2+5 ?
The answer to |x^2+x-5|=x^2+5 is x=-1/2 \lor x=0\lor x=10
Solve for x: |x^2+x-5|=x^2+5
The solution is x=-1/2 \lor x=0\lor x=10