What is the answer to |x^2-3x-1|=2-x ?

The answer to |x^2-3x-1|=2-x is x=-1\lor x=2-sqrt(3)

Solve for x: |x^2-3x-1|=2-x

The solution is x=-1\lor x=2-sqrt(3)

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x^{2} - 3 x - 1 = 2 - x

x = - 1 or x = 2 - 3

Decimal

x = - 1, x = 0.26794 \dots

Solution steps

x^{2} - 3 x - 1 = 2 - x

Find positive and negative intervals

x \leq \frac{- 13 + 3}{2}, \frac{- 13 + 3}{2} < x < \frac{13 + 3}{2}, x \geq \frac{13 + 3}{2}

Solve the inequality for each interval

x = - 1 or x = 2 - 3 or No Solution

x = - 1 or x = 2 - 3

3 ∣ x - 3 ∣ + 10 = 13

∣ f ∣ - \frac{2}{3} = \frac{5}{6}

∣ 3 x - 2 ∣ = x - 6

x^{2} - 6 = ∣ 5 x ∣

∣ 2 x - 1 ∣ = 19

What is the answer to |x^2-3x-1|=2-x ?
The answer to |x^2-3x-1|=2-x is x=-1\lor x=2-sqrt(3)
Solve for x: |x^2-3x-1|=2-x
The solution is x=-1\lor x=2-sqrt(3)