What is the answer to x^2-3x+2|x-2|=0 ?

The answer to x^2-3x+2|x-2|=0 is x=1\lor x=(1+sqrt(17))/2

Solve for x: x^2-3x+2|x-2|=0

The solution is x=1\lor x=(1+sqrt(17))/2

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x^{2} - 3 x + 2 ∣ x - 2 ∣ = 0

x = 1 or x = \frac{1 + 17}{2}

Decimal

x = 1, x = 2.56155 \dots

Solution steps

x^{2} - 3 x + 2 ∣ x - 2 ∣ = 0

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

x = 1 or x = \frac{1 + 17}{2}

- 2 ∣ x - 1 ∣ + 3 = 3

12 - 5 ∣ x - 2 ∣ = 2

y, y - 3 = ∣ x - 4 ∣

3 = ∣ x ∣ + 1

23 = ∣ n + 10 ∣

What is the answer to x^2-3x+2|x-2|=0 ?
The answer to x^2-3x+2|x-2|=0 is x=1\lor x=(1+sqrt(17))/2
Solve for x: x^2-3x+2|x-2|=0
The solution is x=1\lor x=(1+sqrt(17))/2