What is the answer to x^2+|x-1|=11+2x ?

The answer to x^2+|x-1|=11+2x is x=-2\lor x=4

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x^2+|x-1|=11+2x

x^{2} + ∣ x - 1 ∣ = 11 + 2 x

x = - 2 or x = 4

Solution steps

x^{2} + ∣ x - 1 ∣ = 11 + 2 x

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

x = - 2 or x = 4

∣ 2 b - 9 ∣ = ∣ b - 6 ∣

∣ x - 2 ∣ \cdot + (x - 1) \cdot + (x + 1) \cdot + (x + 2) = 4

∣ - 2 x + 3 ∣ = ∣ 5 x - 1 ∣

∣ x ∣ + 2 = 11

∣ x + 4 ∣ = ∣ x - 8 ∣

What is the answer to x^2+|x-1|=11+2x ?
The answer to x^2+|x-1|=11+2x is x=-2\lor x=4
Solve for x: x^2+|x-1|=11+2x
The solution is x=-2\lor x=4