What is the answer to 3|x|+x^2-2=0 ?

The answer to 3|x|+x^2-2=0 is x=(3-sqrt(17))/2 \lor x=(-3+sqrt(17))/2

Solve for x: 3|x|+x^2-2=0

The solution is x=(3-sqrt(17))/2 \lor x=(-3+sqrt(17))/2

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3 ∣ x ∣ + x^{2} - 2 = 0

x = \frac{3 - 17}{2} or x = \frac{- 3 + 17}{2}

Decimal

x = - 0.56155 \dots, x = 0.56155 \dots

Solution steps

3 ∣ x ∣ + x^{2} - 2 = 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = \frac{3 - 17}{2} or x = \frac{- 3 + 17}{2}

x, 3 ∣ x + 24 ∣ + 4 = 64

∣ a + 1 ∣ - 6 = 1

∣ x ∣ = x^{3} + 2 x^{2} - 3 x

∣ x + 3 ∣ = 2 x + 4

2 ∣ x + 1 ∣ - ∣ 2 x - 4 ∣ = 1

What is the answer to 3|x|+x^2-2=0 ?
The answer to 3|x|+x^2-2=0 is x=(3-sqrt(17))/2 \lor x=(-3+sqrt(17))/2
Solve for x: 3|x|+x^2-2=0
The solution is x=(3-sqrt(17))/2 \lor x=(-3+sqrt(17))/2