What is the answer to |x^2+x-4|=2 ?

The answer to |x^2+x-4|=2 is x=-3\lor x=-2\lor x=1\lor x=2

Solve for x: |x^2+x-4|=2

The solution is x=-3\lor x=-2\lor x=1\lor x=2

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x^{2} + x - 4 = 2

x = - 3 or x = - 2 or x = 1 or x = 2

Solution steps

x^{2} + x - 4 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + x - 4 = - 2 or x^{2} + x - 4 = 2

x^{2} + x - 4 = - 2 or x^{2} + x - 4 = 2

(x = - 2 or x = 1) or (x = - 3 or x = 2)

x = - 3 or x = - 2 or x = 1 or x = 2

∣ x + 1 ∣ + 2 = 7

5 = - ∣ x - 2 ∣ + 1

∣ x + 9 ∣ = 14

∣ 2 x - 1 ∣ = x^{2} + 1

25 - ∣ x ∣ = 24

What is the answer to |x^2+x-4|=2 ?
The answer to |x^2+x-4|=2 is x=-3\lor x=-2\lor x=1\lor x=2
Solve for x: |x^2+x-4|=2
The solution is x=-3\lor x=-2\lor x=1\lor x=2