What is the answer to 37-10x=|7-35|-x^2 ?

The answer to 37-10x=|7-35|-x^2 is x=1\lor x=9

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37-10x=|7-35|-x^2

37 - 10 x = ∣ 7 - 35 ∣ - x^{2}

x = 1 or x = 9

Solution steps

37 - 10 x = ∣ 7 - 35 ∣ - x^{2}

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

(x = 1 or x = 9)

x = 1 or x = 9

\frac{1}{4} x - 3 + 1 = 11

∣ 3 x - 12 ∣ = 6

\frac{x + 5}{2} + 3 = 2

∣ x - 3 ∣ + ∣ 1 - x ∣ = 2

0 = \frac{2}{3} - x

What is the answer to 37-10x=|7-35|-x^2 ?
The answer to 37-10x=|7-35|-x^2 is x=1\lor x=9
Solve for x: 37-10x=|7-35|-x^2
The solution is x=1\lor x=9