What is the answer to |x^2+5x|=|4-x| ?

The answer to |x^2+5x|=|4-x| is x=-3-sqrt(13)\lor x=-2\lor x=-3+sqrt(13)

Solve for x: |x^2+5x|=|4-x|

The solution is x=-3-sqrt(13)\lor x=-2\lor x=-3+sqrt(13)

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x^{2} + 5 x = ∣ 4 - x ∣

x = - 3 - 13 or x = - 2 or x = - 3 + 13

Decimal

x = - 6.60555 \dots, x = - 2, x = 0.60555 \dots

Solution steps

x^{2} + 5 x = ∣ 4 - x ∣

Find positive and negative intervals

x \leq - 5, - 5 < x < 0, 0 \leq x \leq 4, x > 4

Solve the inequality for each interval

x = - 3 - 13 or x = - 2 or x = - 3 + 13 or No Solution

x = - 3 - 13 or x = - 2 or x = - 3 + 13

- 3 ∣ y - 4 ∣ = 6

- x^{2} + 5 x - 6 = ∣ x - 3 ∣ - 9

∣ 7 x + 5 ∣ = 16

∣ x - 4 ∣ = ∣ 5 - 2 ∣

x^{2} - 7 x - 9 - 9 = 0

What is the answer to |x^2+5x|=|4-x| ?
The answer to |x^2+5x|=|4-x| is x=-3-sqrt(13)\lor x=-2\lor x=-3+sqrt(13)
Solve for x: |x^2+5x|=|4-x|
The solution is x=-3-sqrt(13)\lor x=-2\lor x=-3+sqrt(13)