What is the answer to 2|3x-3|2x= 1/12 ?

The answer to 2|3x-3|2x= 1/12 is x=(6-sqrt(35))/(12)\lor x=(6+sqrt(35))/(12)\lor x=(6+sqrt(37))/(12)

Solve for x: 2|3x-3|2x= 1/12

The solution is x=(6-sqrt(35))/(12)\lor x=(6+sqrt(35))/(12)\lor x=(6+sqrt(37))/(12)

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2 ∣ 3 x - 3 ∣ 2 x = \frac{1}{12}

x = \frac{6 - 35}{12} or x = \frac{6 + 35}{12} or x = \frac{6 + 37}{12}

Decimal

x = 0.00699 \dots, x = 0.99300 \dots, x = 1.00689 \dots

Solution steps

2 ∣ 3 x - 3 ∣ \cdot 2 x = \frac{1}{12}

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

(x = \frac{6 - 35}{12} or x = \frac{6 + 35}{12}) or x = \frac{6 + 37}{12}

x = \frac{6 - 35}{12} or x = \frac{6 + 35}{12} or x = \frac{6 + 37}{12}

∣ 2 x - 3 ∣ + 6 = 2

z^{2} = ∣ z ∣ + 2

∣ 8 x - 1 ∣ - 8 = - 16

\frac{- 2 x}{3} + 2 = 3

3 - \frac{3}{2} x + 8 + 9 = 24

What is the answer to 2|3x-3|2x= 1/12 ?
The answer to 2|3x-3|2x= 1/12 is x=(6-sqrt(35))/(12)\lor x=(6+sqrt(35))/(12)\lor x=(6+sqrt(37))/(12)
Solve for x: 2|3x-3|2x= 1/12
The solution is x=(6-sqrt(35))/(12)\lor x=(6+sqrt(35))/(12)\lor x=(6+sqrt(37))/(12)