What is the answer to sqrt(x^2-4x+4)=8-|2-x| ?

The answer to sqrt(x^2-4x+4)=8-|2-x| is x=-2\lor x=6

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sqrt(x^2-4x+4)=8-|2-x|

x^{2} - 4 x + 4 = 8 - ∣ 2 - x ∣

x = - 2 or x = 6

Solution steps

x^{2} - 4 x + 4 = 8 - ∣ 2 - x ∣

Find positive and negative intervals

x \leq 2, x > 2

Solve the inequality for each interval

x = - 2 or x = 6

x^{3} - x ∣ x ∣ - 15 = 0

f, x = f - 7^{2}

∣ 3 x + 2 ∣ - ∣ x - 1 ∣ = 2 x + 3

x, 2 ∣ 3 x + 1 ∣ - 4 = 6

0.5 = ∣ x - 98.6 ∣

What is the answer to sqrt(x^2-4x+4)=8-|2-x| ?
The answer to sqrt(x^2-4x+4)=8-|2-x| is x=-2\lor x=6
Solve for x: sqrt(x^2-4x+4)=8-|2-x|
The solution is x=-2\lor x=6