What is the answer to |x^2-2sqrt(2)x+2|=18 ?

The answer to |x^2-2sqrt(2)x+2|=18 is x=-2sqrt(2)\lor x=4sqrt(2)

Solve for x: |x^2-2sqrt(2)x+2|=18

The solution is x=-2sqrt(2)\lor x=4sqrt(2)

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x^{2} - 22 x + 2 = 18

x = - 22 or x = 42

Decimal

x = - 2.82842 \dots, x = 5.65685 \dots

Solution steps

x^{2} - 22 x + 2 = 18

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 22 x + 2 = - 18 or x^{2} - 22 x + 2 = 18

x^{2} - 22 x + 2 = - 18 or x^{2} - 22 x + 2 = 18

No Solution or (x = - 22 or x = 42)

x = - 22 or x = 42

∣ 5 x + 1 ∣ = 5

2 ∣ x - 1 ∣ - 8 = 6

u, ∣ 2 u + 14 ∣ = - 6

6 ∣ r - 1 ∣ = 0

∣ x ∣ = - 11.5

What is the answer to |x^2-2sqrt(2)x+2|=18 ?
The answer to |x^2-2sqrt(2)x+2|=18 is x=-2sqrt(2)\lor x=4sqrt(2)
Solve for x: |x^2-2sqrt(2)x+2|=18
The solution is x=-2sqrt(2)\lor x=4sqrt(2)