What is the answer to |x-3|^2+|7x-21|-15=0 ?

The answer to |x-3|^2+|7x-21|-15=0 is x=(13-sqrt(109))/2 \lor x=(-1+sqrt(109))/2

Solve for x: |x-3|^2+|7x-21|-15=0

The solution is x=(13-sqrt(109))/2 \lor x=(-1+sqrt(109))/2

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∣ x - 3 ∣^{2} + ∣ 7 x - 21 ∣ - 15 = 0

x = \frac{13 - 109}{2} or x = \frac{- 1 + 109}{2}

Decimal

x = 1.27984 \dots, x = 4.72015 \dots

Solution steps

∣ x - 3 ∣^{2} + ∣ 7 x - 21 ∣ - 15 = 0

Find positive and negative intervals

x < 3, x \geq 3

Solve the inequality for each interval

x = \frac{13 - 109}{2} or x = \frac{- 1 + 109}{2}

∣ 1 + x ∣ = 9

∣ 3 x + 1 ∣ + ∣ 2 x - 1 ∣ = 0

∣ 3 y + 7 ∣ = ∣ 5 y - 4 ∣

4 + 2 ∣ x - 4 ∣ = 10

\frac{1}{3} ∣ 6 x + 6 ∣ + 4 = 14

What is the answer to |x-3|^2+|7x-21|-15=0 ?
The answer to |x-3|^2+|7x-21|-15=0 is x=(13-sqrt(109))/2 \lor x=(-1+sqrt(109))/2
Solve for x: |x-3|^2+|7x-21|-15=0
The solution is x=(13-sqrt(109))/2 \lor x=(-1+sqrt(109))/2