What is the answer to |u^2-7u|=12 ?

The answer to |u^2-7u|=12 is u=(7-sqrt(97))/2 \lor u=3\lor u=4\lor u=(7+sqrt(97))/2

Solve for u: |u^2-7u|=12

The solution is u=(7-sqrt(97))/2 \lor u=3\lor u=4\lor u=(7+sqrt(97))/2

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u^{2} - 7 u = 12

u = \frac{7 - 97}{2} or u = 3 or u = 4 or u = \frac{7 + 97}{2}

Decimal

u = - 1.42442 \dots, u = 3, u = 4, u = 8.42442 \dots

Solution steps

u^{2} - 7 u = 12

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

u^{2} - 7 u = - 12 or u^{2} - 7 u = 12

u^{2} - 7 u = - 12 or u^{2} - 7 u = 12

(u = 3 or u = 4) or (u = \frac{7 - 97}{2} or u = \frac{7 + 97}{2})

u = \frac{7 - 97}{2} or u = 3 or u = 4 or u = \frac{7 + 97}{2}

∣ - 7 x ∣ = 35

2 ∣ x ∣ = ∣ x - 4 ∣

∣ 2 x + 3 ∣ - 5 - 5 x = - 4

∣ 2 x + 14 ∣ = 0

∣ y + 16 ∣ = 34

What is the answer to |u^2-7u|=12 ?
The answer to |u^2-7u|=12 is u=(7-sqrt(97))/2 \lor u=3\lor u=4\lor u=(7+sqrt(97))/2
Solve for u: |u^2-7u|=12
The solution is u=(7-sqrt(97))/2 \lor u=3\lor u=4\lor u=(7+sqrt(97))/2