What is the answer to |x^2-7x|=12 ?

The answer to |x^2-7x|=12 is x=(7-sqrt(97))/2 \lor x=3\lor x=4\lor x=(7+sqrt(97))/2

Solve for x: |x^2-7x|=12

The solution is x=(7-sqrt(97))/2 \lor x=3\lor x=4\lor x=(7+sqrt(97))/2

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x^{2} - 7 x = 12

x = \frac{7 - 97}{2} or x = 3 or x = 4 or x = \frac{7 + 97}{2}

Decimal

x = - 1.42442 \dots, x = 3, x = 4, x = 8.42442 \dots

Solution steps

x^{2} - 7 x = 12

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 7 x = - 12 or x^{2} - 7 x = 12

x^{2} - 7 x = - 12 or x^{2} - 7 x = 12

(x = 3 or x = 4) or (x = \frac{7 - 97}{2} or x = \frac{7 + 97}{2})

x = \frac{7 - 97}{2} or x = 3 or x = 4 or x = \frac{7 + 97}{2}

∣ 2 x ∣ = - 7

∣ x + 3 ∣ + ∣ x - 1 ∣ = 6

∣ 2 x ∣ = - 9

4 ∣ 8 x - 6 ∣ = 5 ∣ - 8 x + 7 ∣

∣ 5 x - 1 ∣ = ∣ x + 12 ∣

What is the answer to |x^2-7x|=12 ?
The answer to |x^2-7x|=12 is x=(7-sqrt(97))/2 \lor x=3\lor x=4\lor x=(7+sqrt(97))/2
Solve for x: |x^2-7x|=12
The solution is x=(7-sqrt(97))/2 \lor x=3\lor x=4\lor x=(7+sqrt(97))/2