What is the answer to |7r-3|=|4r+15| ?

The answer to |7r-3|=|4r+15| is r=-12/11 \lor r=6

Solve for r: |7r-3|=|4r+15|

The solution is r=-12/11 \lor r=6

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∣ 7 r - 3 ∣ = ∣ 4 r + 15 ∣

r = - \frac{12}{11} or r = 6

Decimal

r = - 1.09090 \dots, r = 6

Solution steps

∣ 7 r - 3 ∣ = ∣ 4 r + 15 ∣

Find positive and negative intervals

r < - \frac{15}{4}, - \frac{15}{4} \leq r < \frac{3}{7}, r \geq \frac{3}{7}

Solve the inequality for each interval

No Solution or r = - \frac{12}{11} or r = 6

r = - \frac{12}{11} or r = 6

∣ 5 x - 9 ∣ - 8 = - 1

\frac{∣ x + 1 ∣}{3} = 3

2 ∣ 5 x - 4 ∣ - 5 = 9

∣ 7 x ∣ = 12

∣ 5 - 4 x ∣ = 0

What is the answer to |7r-3|=|4r+15| ?
The answer to |7r-3|=|4r+15| is r=-12/11 \lor r=6
Solve for r: |7r-3|=|4r+15|
The solution is r=-12/11 \lor r=6