What are the solutions to the equation factor x^2-4x=21 ?

The solutions to the equation factor x^2-4x=21 are x=-3,x=7

Find the zeros of factor x^2-4x=21

The zeros of factor x^2-4x=21 are x=-3,x=7

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x^{2} - 4 x = 21

x = - 3, x = 7

Solution steps

x^{2} - 4 x = 21

Move

21

to the left side

x^{2} - 4 x - 21 = 0

Factor

x^{2} - 4 x - 21 : (x + 3) (x - 7)

(x + 3) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 7 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = - 3, x = 7

40/5

\frac{6}{( 6 )}

b, 14 - \frac{b}{8} = 17

27 x^{3}

c, f = \frac{9}{5 c + 32}

What are the solutions to the equation factor x^2-4x=21 ?
The solutions to the equation factor x^2-4x=21 are x=-3,x=7
Find the zeros of factor x^2-4x=21
The zeros of factor x^2-4x=21 are x=-3,x=7