What is expand (2x+1)(x-3)(x-2) ?

The solution to expand (2x+1)(x-3)(x-2) is 2x^3-9x^2+7x+6

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Write in Standard Form (2x+1)(x-3)(x-2)

expand

(2 x + 1) (x - 3) (x - 2)

2 x^{3} - 9 x^{2} + 7 x + 6

Solution steps

(2 x + 1) (x - 3) (x - 2)

Expand

(2 x + 1) (x - 3) (x - 2) : (2 x^{2} - 5 x - 3) (x - 2)

= (2 x^{2} - 5 x - 3) (x - 2)

Distribute parentheses

= 2 x^{2} x + 2 x^{2} (- 2) - 5 xx - 5 x (- 2) - 3 x - 3 (- 2)

Simplify

2 x^{2} x + 2 x^{2} (- 2) - 5 xx - 5 x (- 2) - 3 x - 3 (- 2) : 2 x^{3} - 9 x^{2} + 7 x + 6

= 2 x^{3} - 9 x^{2} + 7 x + 6

x, 2 (4 + 2 x) \geq 5 x + 5

g, 19 g + 3 g - 18 g - 2 g = 14

8 x^{3}

18 x^{2}

54/9

What is expand (2x+1)(x-3)(x-2) ?
The solution to expand (2x+1)(x-3)(x-2) is 2x^3-9x^2+7x+6