What is the answer to solvefor m,((2m^2+3m-5))/((m^2+4m-5))=4 ?

The answer to solvefor m,((2m^2+3m-5))/((m^2+4m-5))=4 is m=-15/2

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Solve for m (2m^2+3m-5)/(m^2+4m-5)=4

solve for

m, \frac{( 2 m ^{2} + 3 m - 5 )}{( m ^{2} + 4 m - 5 )} = 4

m = - \frac{15}{2}

Decimal

m = - 7.5

Solution steps

\frac{( 2 m ^{2} + 3 m - 5 )}{( m ^{2} + 4 m - 5 )} = 4

Simplify

\frac{2 m ^{2} + 3 m - 5}{m ^{2} + 4 m - 5} : \frac{2 m + 5}{m + 5}

\frac{2 m + 5}{m + 5} = 4

Multiply both sides by

m + 5

2 m + 5 = 4 (m + 5)

Expand

4 (m + 5) : 4 m + 20

2 m + 5 = 4 m + 20

Move

5

to the right side

2 m = 4 m + 15

Move

4 m

to the left side

- 2 m = 15

Divide both sides by

- 2

m = - \frac{15}{2}

Verify Solutions

Find undefined (singularity) points:

m = 1, m = - 5

Combine undefined points with solutions:

m = - \frac{15}{2}

cos (13 5^{\circ})

- 56/7

x, 7^{x} = 12

4.59%

- 4 (3 x - 5)

What is the answer to solvefor m,((2m^2+3m-5))/((m^2+4m-5))=4 ?
The answer to solvefor m,((2m^2+3m-5))/((m^2+4m-5))=4 is m=-15/2