What are the solutions to the equation quadraticformula x^2-5x=12 ?

The solutions to the equation quadraticformula x^2-5x=12 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2

Find the zeros of quadraticformula x^2-5x=12

The zeros of quadraticformula x^2-5x=12 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2

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x^{2} - 5 x = 12

x = \frac{5 + 73}{2}, x = \frac{5 - 73}{2}

Decimal

x = 6.77200 \dots, x = - 1.77200 \dots

Solution steps

x^{2} - 5 x = 12

Move

12

to the left side

x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 12) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 1}

x = \frac{- ( - 5 ) + 73}{2 \cdot 1} : \frac{5 + 73}{2}

x = \frac{- ( - 5 ) - 73}{2 \cdot 1} : \frac{5 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{2}, x = \frac{5 - 73}{2}

\frac{5}{( 5 + i )}

48 x^{3}

3 x^{2} + 54 x + 243

48/8

x, 8 x - 3 = 5

What are the solutions to the equation quadraticformula x^2-5x=12 ?
The solutions to the equation quadraticformula x^2-5x=12 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2
Find the zeros of quadraticformula x^2-5x=12
The zeros of quadraticformula x^2-5x=12 are x=(5+sqrt(73))/2 ,x=(5-sqrt(73))/2