What are the solutions to the equation quadraticformula x^2-4x-3=0 ?

The solutions to the equation quadraticformula x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)

Find the zeros of quadraticformula x^2-4x-3=0

The zeros of quadraticformula x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)

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x^{2} - 4 x - 3 = 0

x = 2 + 7, x = 2 - 7

Decimal

x = 4.64575 \dots, x = - 0.64575 \dots

Solution steps

x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

x = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

x = 2 + 7, x = 2 - 7

540%

t, 16 - 2 t = \frac{3}{2 t + 9}

x, 8 = x^{2}

72 x^{3}

\frac{100}{( 70% )}

What are the solutions to the equation quadraticformula x^2-4x-3=0 ?
The solutions to the equation quadraticformula x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)
Find the zeros of quadraticformula x^2-4x-3=0
The zeros of quadraticformula x^2-4x-3=0 are x=2+sqrt(7),x=2-sqrt(7)