What are the solutions to the equation quadraticformula x^2-14x=-45 ?

The solutions to the equation quadraticformula x^2-14x=-45 are x=9,x=5

Find the zeros of quadraticformula x^2-14x=-45

The zeros of quadraticformula x^2-14x=-45 are x=9,x=5

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x^{2} - 14 x = - 45

x = 9, x = 5

Solution steps

x^{2} - 14 x = - 45

Move

45

to the left side

x^{2} - 14 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 45 = 4

x_{1, 2} = \frac{- ( - 14 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4}{2 \cdot 1} : 9

x = \frac{- ( - 14 ) - 4}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 9, x = 5

x^{2} - 2 x - 80 = 0

2 x - 7

60 = 15

5 x + 12 = 0

x^{2} = 9 x - 20

What are the solutions to the equation quadraticformula x^2-14x=-45 ?
The solutions to the equation quadraticformula x^2-14x=-45 are x=9,x=5
Find the zeros of quadraticformula x^2-14x=-45
The zeros of quadraticformula x^2-14x=-45 are x=9,x=5