What are the solutions to the equation quadraticformula 2x^2-x-4=0 ?

The solutions to the equation quadraticformula 2x^2-x-4=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4

Find the zeros of quadraticformula 2x^2-x-4=0

The zeros of quadraticformula 2x^2-x-4=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - x - 4 = 0

x = \frac{1 + 33}{4}, x = \frac{1 - 33}{4}

Decimal

x = 1.68614 \dots, x = - 1.18614 \dots

Solution steps

2 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 4) = 33

x_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 33}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 33}{2 \cdot 2}

x = \frac{- ( - 1 ) + 33}{2 \cdot 2} : \frac{1 + 33}{4}

x = \frac{- ( - 1 ) - 33}{2 \cdot 2} : \frac{1 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 33}{4}, x = \frac{1 - 33}{4}

x, 14 = - (x - 8)

- \frac{14}{35}

x, 6^{x^{2}} = 28

x, 3 x^{2} = 75

16

What are the solutions to the equation quadraticformula 2x^2-x-4=0 ?
The solutions to the equation quadraticformula 2x^2-x-4=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4
Find the zeros of quadraticformula 2x^2-x-4=0
The zeros of quadraticformula 2x^2-x-4=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4