vereinfachen (16x^8y^{-12})^{1/2}

Lösung

vereinfachen

(16 x^{8} y^{- 12})^{\frac{1}{2}}

\frac{4 x ^{4}}{y ^{6}}

Schritte zur Lösung

(16 x^{8} y^{- 12})^{\frac{1}{2}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(16 x^{8} y^{- 12})^{\frac{1}{2}} = 1 6^{\frac{1}{2}} (x^{8})^{\frac{1}{2}} (y^{- 12})^{\frac{1}{2}}

= 1 6^{\frac{1}{2}} (x^{8})^{\frac{1}{2}} (y^{- 12})^{\frac{1}{2}}

1 6^{\frac{1}{2}} = 4

= 4 (x^{8})^{\frac{1}{2}} (y^{- 12})^{\frac{1}{2}}

Vereinfache

(x^{8})^{\frac{1}{2}} : x^{4}

= 4 x^{4} (y^{- 12})^{\frac{1}{2}}

Vereinfache

(y^{- 12})^{\frac{1}{2}} : \frac{1}{y ^{6}}

= 4 x^{4} \frac{1}{y ^{6}}

Vereinfache

4 x^{4} \frac{1}{y ^{6}} : \frac{4 x ^{4}}{y ^{6}}

= \frac{4 x ^{4}}{y ^{6}}

f a c t or 8 x^{2} + 40 x + 50

4^{2} + 9 (4) + 2

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