x^2+0.00022x-0.0004345=0

解答

x^{2} + 0.00022 x - 0.0004345 = 0

x = \frac{- 0.00022 + 0.0017380484}{2}, x = \frac{- 0.00022 - 0.0017380484}{2}

十进制

x = 0.02073 \dots, x = - 0.02095 \dots

求解步骤

x^{2} + 0.00022 x - 0.0004345 = 0

使用求根公式求解

x_{1, 2} = \frac{- 0.00022 \pm 0.0002 2 ^{2} - 4 \cdot 1 \cdot ( - 0.0004345 )}{2 \cdot 1}

0.0002 2^{2} - 4 \cdot 1 \cdot (- 0.0004345) = 0.0017380484

x_{1, 2} = \frac{- 0.00022 \pm 0.0017380484}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 0.00022 + 0.0017380484}{2 \cdot 1}, x_{2} = \frac{- 0.00022 - 0.0017380484}{2 \cdot 1}

x = \frac{- 0.00022 + 0.0017380484}{2 \cdot 1} : \frac{- 0.00022 + 0.0017380484}{2}

x = \frac{- 0.00022 - 0.0017380484}{2 \cdot 1} : \frac{- 0.00022 - 0.0017380484}{2}

二次方程组的解是:

x = \frac{- 0.00022 + 0.0017380484}{2}, x = \frac{- 0.00022 - 0.0017380484}{2}

l o n g s u b 15.816 - 14.452

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