faktorisieren a^5+1

Lösung

faktorisieren

a^{5} + 1

(a + 1) (a^{4} - a^{3} + a^{2} - a + 1)

Schritte zur Lösung

a^{5} + 1

Schreibe

1

um:

1^{5}

= a^{5} + 1^{5}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1}), n i s o dd

a^{5} + 1^{5} = (a + 1) (a^{4} - a^{3} + a^{2} - a + 1)

= (a + 1) (a^{4} - a^{3} + a^{2} - a + 1)

4 x^{2} + 8 x + 9 = 0

- 2 \leq \frac{1 - x}{2} < 10

x - 20 = \frac{20 + x}{3}

y^{2} = 25

f a c t or 9 n^{2} - 25