(\partial)/(\partial v)(u^2-v^2)

解答

\frac{\partial}{\partial v} (u^{2} - v^{2})

- 2 v

求解步骤

\frac{\partial}{\partial v} (u^{2} - v^{2})

将

u

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u^{2}) - \frac{\partial}{\partial v} (v^{2})

\frac{\partial}{\partial v} (u^{2}) = 0

\frac{\partial}{\partial v} (v^{2}) = 2 v

= 0 - 2 v

化简

= - 2 v

\int - 3 cos (2 x) d x

\int \frac{2 ^{x}}{x} d x

\int 1 - 6 x d x

\int_{0}^{\frac{π}{4}} cot (x) d x

t an g e n t f (x) = 5 x - 4 x^{2}, (- 1, - 9)