What is the sum from n=0 to infinity of-n/(2^n) ?

The sum from n=0 to infinity of-n/(2^n) is converges

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sum from n=0 to infinity of-n/(2^n)

n = 0 \sum \infty - \frac{n}{2 ^{n}}

converges

Solution steps

n = 0 \sum \infty - \frac{n}{2 ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - n = 0 \sum \infty \frac{n}{2 ^{n}}

Apply Series Ratio Test:

converges

= - converges

= converges

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What is the sum from n=0 to infinity of-n/(2^n) ?
The sum from n=0 to infinity of-n/(2^n) is converges