What is the slope of y= 6/((x-1)^2),\at ?

The slope of y= 6/((x-1)^2),\at is -(12)/((x-1)^3)

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slope of y= 6/((x-1)^2),\at

slope

y = \frac{6}{( x - 1 ) ^{2}}, at

- \frac{12}{( x - 1 ) ^{3}}

Solution steps

y = \frac{6}{( x - 1 ) ^{2}}

In order to find the slope of the function, take the derivative of

\frac{6}{( x - 1 ) ^{2}}

\frac{d}{d x} (\frac{6}{( x - 1 ) ^{2}}) = - \frac{12}{( x - 1 ) ^{3}}

- \frac{12}{( x - 1 ) ^{3}}

\frac{d}{d x} ((sec (4 x) + tan (2 x))^{5})

\frac{d}{d x} ((x^{2} + 3 x) (x - 2) (x^{2} + 1))

y = 2 x - x^{2}, (0, 2)

9 sin (3 x)

\int_{0}^{1} - x + 2 d x

What is the slope of y= 6/((x-1)^2),\at ?
The slope of y= 6/((x-1)^2),\at is -(12)/((x-1)^3)