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Popular >

y^{''}-8y^'+16=0

Solution

y^{^{''}} - 8 y^{^{'}} + 16 = 0

Solution

y = c_{1} e^{8 t} + c_{2} + 2 t

Solution steps

y^{''} (t) - 8 y^{'} (t) + 16 = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} + 2 t

y = c_{1} e^{8 t} + c_{2} + 2 t

Popular Examples

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x \to π lim ((π - x) cot (x))

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derivative of e^{8x}cos(11x)derivative of

e^{8 x} cos (11 x)

integral of X^{-1}

\int X^{- 1} d X

roots 3xy roots

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-8y^'+16=0 ?
The solution for y^{''}-8y^'+16=0 is y=c_{1}e^{8t}+c_{2}+2t