What is area 7x^2,x^2+1 ?

The answer to area 7x^2,x^2+1 is -(sqrt(2))/(3sqrt(3))+sqrt(2/3)

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area 7x^2,x^2+1

area

7 x^{2}, x^{2} + 1

- \frac{2}{3 3} + \frac{2}{3}

Solution steps

Apply the area formula:

\int_{- \frac{1}{6}}^{\frac{1}{6}} 7 x^{2} - (x^{2} + 1) d x

Solve

\int_{- \frac{1}{6}}^{\frac{1}{6}} 7 x^{2} - (x^{2} + 1) d x : - \frac{2}{3 3} + \frac{2}{3}

The area is:

= - \frac{2}{3 3} + \frac{2}{3}

\int e^{x} 3 + e^{x} d x

\frac{\partial}{\partial y} (sin (x) + x^{2} e^{y} - 1)

\frac{d}{d x} (\frac{6 x}{5 - cot ( x )})

\int \frac{1}{2 + sin ( x ) + 3 cos ( x )} d x

\frac{d}{d x} (2 x^{2} + 2 y^{2})

What is area 7x^2,x^2+1 ?
The answer to area 7x^2,x^2+1 is -(sqrt(2))/(3sqrt(3))+sqrt(2/3)