What is the sum from n=0 to infinity of 1+2+3+4+5 ?

The sum from n=0 to infinity of 1+2+3+4+5 is diverges

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sum from n=0 to infinity of 1+2+3+4+5

n = 0 \sum \infty 1 + 2 + 3 + 4 + 5

diverges

Solution steps

n = 0 \sum \infty 1 + 2 + 3 + 4 + 5

Every infinite sum of a non-zero constant diverges

= diverges

\frac{d}{d x} (\frac{e ^{a r c t a n (x)}}{x ^{2} + 1})

\int (\frac{x}{2} + 1) d x

\frac{d}{d x} (cos (\frac{π}{2} - 3 x))

\frac{\partial}{\partial x} (\frac{4 x - 2 y}{3 x ^{2} + 2 y})

\frac{d y}{d x} = \frac{- 2 x y + 1}{x ^{2} + 2 y}

What is the sum from n=0 to infinity of 1+2+3+4+5 ?
The sum from n=0 to infinity of 1+2+3+4+5 is diverges