What is the tangent of f(x)=8tan(x),(pi/4 ,8) ?

The tangent of f(x)=8tan(x),(pi/4 ,8) is y=16x+8-4pi

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tangent of f(x)=8tan(x),(pi/4 ,8)

tangent of

f (x) = 8 tan (x), (\frac{π}{4}, 8)

y = 16 x + 8 - 4 π

Solution steps

Find the slope of

f (x) = 8 tan (x) : \frac{df ( x )}{d x} = 8 sec^{2} (x)

Compute the slope of

f (x) = 8 tan (x)

(\frac{π}{4}, 8) : m = 16

Find the line with slope m=

16

and passing through

(\frac{π}{4}, 8) : y = 16 x + 8 - 4 π

y = 16 x + 8 - 4 π

\int \frac{e ^{x + 4}}{x + 4} d x

2 y ln (x) ln (y) d x + d y = 0

(4 - 2 x^{2})^{3}

x^{^{'''}} + x^{^{''}} = 0

\int \frac{( x ^{2} + 1 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

What is the tangent of f(x)=8tan(x),(pi/4 ,8) ?
The tangent of f(x)=8tan(x),(pi/4 ,8) is y=16x+8-4pi