What is the derivative of y=(e^{4x^2}+1)/8 ?

The derivative of y=(e^{4x^2}+1)/8 is e^{4x^2}x

What is the first derivative of y=(e^{4x^2}+1)/8 ?

The first derivative of y=(e^{4x^2}+1)/8 is e^{4x^2}x

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derivative of

y = \frac{e ^{4 x^{2}} + 1}{8}

e^{4 x^{2}} x

Solution steps

\frac{d}{d x} (\frac{e ^{4 x^{2}} + 1}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (e^{4 x^{2}} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8} (\frac{d}{d x} (e^{4 x^{2}}) + \frac{d}{d x} (1))

\frac{d}{d x} (e^{4 x^{2}}) = e^{4 x^{2}} \cdot 8 x

\frac{d}{d x} (1) = 0

= \frac{1}{8} (e^{4 x^{2}} \cdot 8 x + 0)

Simplify

\frac{1}{8} (e^{4 x^{2}} \cdot 8 x + 0) : e^{4 x^{2}} x

= e^{4 x^{2}} x

x \to 1 lim (\frac{x + 7}{x + 3})

\frac{d}{d x} (x^{2 y})

\int ((3 x - 4) e^{- x}) d x

f (x) = \frac{8}{x ^{2} + 4}, at x = 3

\int_{0}^{5} 5 x - x^{2} d x

What is the derivative of y=(e^{4x^2}+1)/8 ?
The derivative of y=(e^{4x^2}+1)/8 is e^{4x^2}x
What is the first derivative of y=(e^{4x^2}+1)/8 ?
The first derivative of y=(e^{4x^2}+1)/8 is e^{4x^2}x