What is the derivative of y^4-2x ?

The derivative of y^4-2x is 4y^3(dy)/(dx)-2

What is the first derivative of y^4-2x ?

The first derivative of y^4-2x is 4y^3(dy)/(dx)-2

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\frac{d}{d x} (y^{4} - 2 x)

4 y^{3} \frac{d y}{d x} - 2

Solution steps

\frac{d}{d x} (y^{4} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{4}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (y^{4}) = 4 y^{3} \frac{d y}{d x}

\frac{d}{d x} (2 x) = 2

= 4 y^{3} \frac{d y}{d x} - 2

\frac{\partial}{\partial z} (x y^{2})

\frac{\partial}{\partial x} (2 x y - 28 x)

\int \frac{x ^{3} + 6 x - 2}{x ^{4} + 6 x ^{2}} d x

\int 5^{- 8 (x - 7)} d x

\int \frac{a}{a - x} d x

What is the derivative of y^4-2x ?
The derivative of y^4-2x is 4y^3(dy)/(dx)-2
What is the first derivative of y^4-2x ?
The first derivative of y^4-2x is 4y^3(dy)/(dx)-2