What is the derivative of f(x)=(x^2)/(8-8x) ?

The derivative of f(x)=(x^2)/(8-8x) is (x(-x+2))/(8(x-1)^2)

What is the first derivative of f(x)=(x^2)/(8-8x) ?

The first derivative of f(x)=(x^2)/(8-8x) is (x(-x+2))/(8(x-1)^2)

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derivative of

f (x) = \frac{x ^{2}}{8 - 8 x}

\frac{x ( - x + 2 )}{8 ( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{8 - 8 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 8 - 8 x ) - \frac{d}{d x} ( 8 - 8 x ) x ^{2}}{( 8 - 8 x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 - 8 x) = - 8

= \frac{2 x ( 8 - 8 x ) - ( - 8 ) x ^{2}}{( 8 - 8 x ) ^{2}}

Simplify

\frac{2 x ( 8 - 8 x ) - ( - 8 ) x ^{2}}{( 8 - 8 x ) ^{2}} : \frac{x ( - x + 2 )}{8 ( x - 1 ) ^{2}}

= \frac{x ( - x + 2 )}{8 ( x - 1 ) ^{2}}

(\frac{1}{y ^{2}} - \frac{5}{y ^{4}}) (y + 9 y^{3})

\frac{d y}{d x} = \frac{1}{10} y (500 - y)

x \to \infty lim (7 x^{2} + 6)

y^{^{'}} = tan (x + y)

\int θ^{4} + 4 θ^{2} d θ

What is the derivative of f(x)=(x^2)/(8-8x) ?
The derivative of f(x)=(x^2)/(8-8x) is (x(-x+2))/(8(x-1)^2)
What is the first derivative of f(x)=(x^2)/(8-8x) ?
The first derivative of f(x)=(x^2)/(8-8x) is (x(-x+2))/(8(x-1)^2)