What is laplacetransform-5sin(3t) ?

The answer to laplacetransform-5sin(3t) is -(15)/(s^2+9)

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laplacetransform-5sin(3t)

laplace transform

- 5 sin (3 t)

- \frac{15}{s ^{2} + 9}

Solution steps

L {- 5 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= - 5 \cdot \frac{3}{s ^{2} + 9}

Refine

- 5 \frac{3}{s ^{2} + 9} : - \frac{15}{s ^{2} + 9}

= - \frac{15}{s ^{2} + 9}

\frac{\partial}{\partial y} (\frac{y ^{2}}{x ^{2} + y ^{2}})

\int - e^{x} x d x

\int \frac{36}{1 + 36 x ^{2}} d x

y^{^{'}} = 1 - 2 y

f (x) = \frac{x}{1 - ln ( x - 4 )}

What is laplacetransform-5sin(3t) ?
The answer to laplacetransform-5sin(3t) is -(15)/(s^2+9)