What is the tangent of f(x)=(1+3x)(5-4x),\at x=1 ?

The tangent of f(x)=(1+3x)(5-4x),\at x=1 is y=-13x+17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(1+3x)(5-4x),\at x=1

tangent of

f (x) = (1 + 3 x) (5 - 4 x), at x = 1

y = - 13 x + 17

Solution steps

Find the tangent point:

(1, 4)

Find the slope of

f (x) = (1 + 3 x) (5 - 4 x) : \frac{df ( x )}{d x} = - 24 x + 11

Compute the slope of

f (x) = (1 + 3 x) (5 - 4 x)

x = 1 : m = - 13

Find the line with slope m=

- 13

and passing through

(1, 4) : y = - 13 x + 17

y = - 13 x + 17

\frac{d}{d x} (a cos (a x))

\int \frac{x ^{3} + 4}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (cos (x - y) + (x + y))

y = x, y = 2 x 25 - x^{2}

\int_{- 2}^{2} - 2 x^{2} + 8 d x

What is the tangent of f(x)=(1+3x)(5-4x),\at x=1 ?
The tangent of f(x)=(1+3x)(5-4x),\at x=1 is y=-13x+17