What is the limit as x approaches 0 of x^2cos(8/x) ?

The limit as x approaches 0 of x^2cos(8/x) is 0

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limit as x approaches 0 of x^2cos(8/x)

x \to 0 lim (x^{2} cos (\frac{8}{x}))

0

Solution steps

x \to 0 lim (x^{2} cos (\frac{8}{x}))

Apply the Squeeze Theorem:

0

= 0

y = \frac{3 x - 2}{x}

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{3} + x + 1})

\frac{\partial}{\partial t} (4 sin (t))

y = \frac{1}{2} x, y = \frac{1}{25} x^{2}, y = 1

x \to 5 lim (\frac{2 x}{x - 5})

What is the limit as x approaches 0 of x^2cos(8/x) ?
The limit as x approaches 0 of x^2cos(8/x) is 0