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Popular >

tangent of-5x^3-1

Solution

tangent of

- 5 x^{3} - 1

Solution

y = - 15 a_{0}^{2} x + 10 a_{0}^{3} - 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 5 a_{0}^{3} - 1)

Find the slope of

y = - 5 x^{3} - 1 : \frac{d y}{d x} = - 15 x^{2}

Compute the slope of

y = - 5 x^{3} - 1

at

x = a_{0} : m = - 15 a_{0}^{2}

Find the line with slope m=

- 15 a_{0}^{2}

and passing through

(a_{0}, - 5 a_{0}^{3} - 1) : y = - 15 a_{0}^{2} x + 10 a_{0}^{3} - 1

y = - 15 a_{0}^{2} x + 10 a_{0}^{3} - 1

Popular Examples

integral of 2cos(sqrt(x))

\int 2 cos (x) d x

y^{^{'}} + 5 y = 0

derivative of x^3e^{1/3 x}+(2x/(5+x))

\frac{d}{d x} (x^{3} e^{\frac{1}{3} x} + \frac{2 x}{5 + x})

integral of 1/(sqrt(1-4x-x^2))

\int \frac{1}{1 - 4 x - x ^{2}} d x

derivative of x^{7/8}

\frac{d}{d x} (x^{\frac{7}{8}})

Frequently Asked Questions (FAQ)

What is the tangent of-5x^3-1 ?
The tangent of-5x^3-1 is y=-15a_{0}^2x+10a_{0}^3-1