What is the derivative of ln(x-9) ?

The derivative of ln(x-9) is 1/(x-9)

What is the first derivative of ln(x-9) ?

The first derivative of ln(x-9) is 1/(x-9)

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derivative of

ln (x - 9)

\frac{1}{x - 9}

Solution steps

\frac{d}{d x} (ln (x - 9))

Apply the chain rule:

\frac{1}{x - 9} \frac{d}{d x} (x - 9)

= \frac{1}{x - 9} \frac{d}{d x} (x - 9)

\frac{d}{d x} (x - 9) = 1

= \frac{1}{x - 9} \cdot 1

Simplify

= \frac{1}{x - 9}

\frac{\partial}{\partial x} ((x + 1)^{2} (x^{2} + 2 x))

f (x) = \frac{x ^{3} - 1 x ^{2} + 2}{x ^{2}}

\int (x x + 3) d x

\frac{\partial}{\partial x} (x^{4} + y^{4} + 3 x^{2} y^{3})

13 + 2 x - x^{2}, 3 x + 1

What is the derivative of ln(x-9) ?
The derivative of ln(x-9) is 1/(x-9)
What is the first derivative of ln(x-9) ?
The first derivative of ln(x-9) is 1/(x-9)